Решите математику плиз

$\frac{(3 \frac{1}{8}- 7\frac{5}{6}):(-4 \frac{17}{24})*(-1,8) }{0,3*(5 \frac{1}{9}* \frac{6}{23}-4):(-1 \frac{1}{3} ) }$
По действия:
1)
$3 \frac{1}{8}- 7\frac{5}{6} = \frac{25}{8}- \frac{47}{6} = \frac{25*3}{8*3}- \frac{47*4}{6*4}= \frac{75-188}{24} =- \frac{113}{24} =-4 \frac{17}{24}$
2)
$-4 \frac{17}{24} :(-4 \frac{17}{24} )= \frac{113*24}{24*113} =1$
3)
$1*(-1,8)=-1,8$
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4)
$5 \frac{1}{9} * \frac{6}{23} = \frac{46}{9} * \frac{6}{23} = \frac{46*6}{9*23} = \frac{2*2}{3*1} = \frac{4}{3} =1 \frac{1}{3}$
5)
$1 \frac{1}{3} -4= -(4- 1\frac{1}{3} )=-(3 \frac{3}{3} - 1\frac{1}{3} )=-2 \frac{2}{3}$
6)
$0.3*(-2 \frac{2}{3} )= \frac{3}{10} *(- \frac{8}{3} )=-( \frac{3*8}{10*3} )=- \frac{8}{10}$
7)
$- \frac{8}{10}:(-1 \frac{1}{3} )= \frac{8}{10} : \frac{4}{3} = \frac{8*3}{10*4} = \frac{2*3}{10*1} = \frac{1*3}{5*1} = \frac{3}{5}$
8)
$-1,8 : \frac{3}{5} = -(\frac{18}{10} : \frac{3}{5} )= -(\frac{18*5}{10*3} )=- \frac{6*1}{2*1} = -\frac{3*1}{1*1} =-3$
Ответ: -3