Метод Лягерра, точность 1e-3
x1 ≈ 0.666666552553487
P(x1) ≈ 0 iter = 4
x2 ≈ 0.749999727053003 − i ∙ 0.66143770861557
P(x2) ≈ 0 iter = 3
x3 ≈ 0.750000123124048 + i ∙ 0.661438012106969
P(x3) ≈ 0 iter = 3
x4 ≈ 1.0000003286761
P(x4) ≈ 0 iter = 1
x5 ≈ 1.49999993526003
P(x5) ≈ 0 iter = 1