1
x≠-2,x≠-5
(x-3)(x+5)=(3x-7)(x+2)
x²+5x-3x-15-3x²-6x+7x+14=0
-2x²+3x-1=0
2x²-3x+1=0
D=9-8=1
x1=(3-1)/4=0,5
x2=(3+1)/4=2
2
x≠0
3x²-7x+4=0
D=49-48=1
x1=(7-1)/6=1
x2=(7+1)/6=4 1/3
3
x≠-4
(3x+1)*(x+4)=20
3x²+12x+x+4-20=0
3x²+13x-16=0
D=169+192=361
x1=(-13+19)/6=-1
x2=(-13-19)/6=-5 1/3
4
x≠0;x≠-1
4(x+1)+10*x=3x(x+1)
3x²+3x-4x-4-10x=0
3x²-11x-4=0
D=121+48=169
x1=(11-13)/6=-1/3
x2=(11+13)/6=4