(2а-а)*(4+2а+а2)-(3+а)*(9-6а+а2)приа=-2

Question

(2а-а)*(4+2а+а2)-(3+а)*(9-6а+а2)приа=-2

Answer 1

(2-a)(2+a)^2-(3+a)(3-a)^2=8-a^3-(3+a)(3-a)(3-a)=8-a^3-(9-a^2)(3-a)= 8-a^3-27+9a+3a^2-a^3=-2a^3+3a^2+9a-19
-2(-2^3)+12-18-19=16+12-18-19=-19 

Comments

cgfcb,j

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спасибо