Помогите решить: 81*(1/3)^4-0.05*(-10)^2 и (-0.2)^0-0.2^3

Question

Помогите решить: 81*(1/3)^4-0.05*(-10)^2 и (-0.2)^0-0.2^3

Answer 1

81*(1/(3^4)-(5/100)*(-10)*(-10)=81/81-(5/100)*100=1-5=-4

(-0.2)^0=1
0.2^3=0.008
1-0.008=0.992