6sin^2x+5sin(p/2-x)=0 [-5p; -7p/2]
6(1-cos²x)+5cosx=0 6cos²x-5cosx-6=0 cosx=a 6a²-5a-6=0 D=25+144=169 a1=(5-13)/12=-2/3 cosx=-2/3 x=π-arccos2/3+2πn,n∈z x=-4π+arccos2/3∈[-5π;-7π/2] a2=(5+13)/12=3/2⇒cosx=1,5>1 нет решения