2cos^2*2x-1=sin4x срочно!!!

Question

2cos^2*2x-1=sin4x срочно!!!

Answer 1

2cos²2x - 1 = sin4x
cos4x = sin4x (cosx ≠ 0)
tg4x = 1
4x = π/4 + πn, n ∈ Z
x = π/16 + πn/4, n ∈ Z.