( (x²+6) /(x² -4) )² =( 5x / (4-x²) )² ;
одз : (x² -4)² =(4-x²) ≠ 0⇒ x ≠ - 2 и x ≠ 2 .
(x²+6 )²=(5x )² ;
x²+6 =| 5x | ;
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a) { x <0 ; x²+6 = - 5x .{ x <0 ; x²+5x+6 =0 .⇒ [ x = -2 ; x =- 3 .<br> x = -2 ∉ одз
x= - 3 .
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b) { x ≥ 0 ; x²+6 = 5x .{ x ≥ 0 ; x²- 5x+6 =0 .⇒ [ x =2 ; x =3 .
x= 2 ∉ одз
x = 3 .
ответ: { -3 ;3}.