решите логарифмическое неравенство log4 (8x+1)<=2

$log_4 (8x+1) \leq 2$
ОДЗ:
$8x+1\ \textgreater \ 0$
$8x\ \textgreater \ -1$
$x\ \textgreater \ -0.125$
$log_4 (8x+1) \leq log_416$
$8x+1 \leq16$
$8x \leq15$
$x \leq 1.875$

-------------------------[1.875]----------------
//////////////////////////////

--------(-0.125)---------------------------------
/////////////////////////////////////////

Ответ: (-0.125; 1.875]