Начнем со второго
2^(x-2)>1/8
2^(x-1)>2^(-3)
x-1>-3
x>-2
log0.1 (x^2-12) < log0.1 -x
одз x<0<br>x^2-12>0 x=(-00 -√12) ( √12 +00)
x<-√12=-2√3 ≈ -3.46<br>x^2-12>-x
x^2-x-12>0
D=1+48=7
x12=(1+-7)/2=-3 4
(x-4)(x+3)>0
+++++++++ -4 --------------- 3 ++++++++
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x=(-00 -4) (3 +00)
x<0<br>x>-2
x=(-00 -2√3) (2√3 +00)
решений нет