Решите неравенство а)(3/4)^1-2x>(4/3)^x+5 б)(2/3)^3x-7>(3/2)^4x+1

Question

Решите неравенство
а)(3/4)^1-2x>(4/3)^x+5
б)(2/3)^3x-7>(3/2)^4x+1

Comments

ага

Answer 1

(3/4)¹⁻²ˣ>(4/3)ˣ⁺⁵
(4/3)²ˣ⁻¹>(4/3)ˣ⁺⁵
2x-1>x+5
x>6.