Решите уравнения x^3 - 3x^2 - 4x + 12 = 0

Question

Решите уравнения x^3 - 3x^2 - 4x + 12 = 0

Answer 1

X^3 - 3x^2 - 4x + 12 = 0

x^2*(x-3)-4(x-3)=0

(x^2-4)*(x-3)=0

(x-2)*(x+2)(x-3)=0


x-2=0 x=2

x+2=0 x=-2

x-3=0 x=3

Otvet:

x1=2

x2=-2

x3=3