(х+4)^2-(х-2)(х+2)=0

Question

(х+4)^2-(х-2)(х+2)=0

Answer 1

(х+4)^2-(х-2)(х+2)=0
х^2+8х+16-(х^2+2х-2х-4)=0
х^2+8х+16-х^2+4=0
8х=-20
х=-20/8
х=-2,5