839 решите пожалуйста срочно нужно

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$1)\;\frac6{4+\frac9{3-\frac3{2+\frac1{1-\frac12}}}}=\frac6{4+\frac9{3-\frac3{2+\frac1{\frac12}}}}=\frac6{4+\frac9{3-\frac3{2+2}}}=\frac6{4+\frac9{3-\frac3{4}}}=\frac6{4+\frac9{{\frac94}}}=\frac6{4+4}=\\=\frac68=\frac34\\2)\;\frac1{8-\frac{19}{6-\frac4{4-\frac1{2-\frac34}}}}=\frac1{8-\frac{19}{6-\frac4{4-\frac1{\frac54}}}}=\frac1{8-\frac{19}{6-\frac4{4-\frac45}}}=\frac1{8-\frac{19}{6-\frac4{\frac{16}5}}}=\\=\frac1{8-\frac{19}{6-\frac54}}=\frac1{8-\frac{19}{\frac{19}4}}=\frac1{8-4}=\frac14$
$3)\;\frac5{7+\frac9{6+\frac5{5+\frac8{4+\frac45}}}}=\frac5{7+\frac9{6+\frac5{5+\frac8{\frac{24}5}}}}=\frac5{7+\frac9{6+\frac5{5+\frac53}}}=\frac5{7+\frac9{6+\frac5{\frac{20}3}}}=\frac5{7+\frac9{6+\frac34}}=\\=\frac5{7+\frac9{\frac{27}4}}=\frac5{7+\frac43}=\frac5{\frac{25}3}=\frac35$