1) 2 - 9х^2 = 0 2) -0,36 - х^2 = 0 3) 7х - 3х^2 = -14 4) 10х^2 - 2 = х

Решите задачу:

$1)\quad 2-9x^2=0\\\\9x^2=2\; ,\; x^2=\frac{9}{2}\; \; \to \; \; x=\pm \frac{3}{\sqrt2}=\pm \frac{3\sqrt2}{2}\\\\2)\quad -0,36-x^2=0\\\\x^2=-0,36\ \textless \ 0\; \; \to \; \; net\; kornej,\; t.k.\; \; x^2 \geq 0\\\\3)\quad 7x-3x^2=-14\\\\3x^2-7x-14=0\\\\D=217\; ,\; \; x_2= \frac{7-\sqrt{217}}{6} \; ,\; \; x_2=\frac{7+\sqrt{217}}{6} \\\\4)\quad 10x^2-2=x\\\\10x^2-x-2=0\\\\D=81\; ,\; \; x_1=\frac{1-9}{20}=-\frac{8}{20}=-\frac{2}{5}\; ,\; \; x_2=\frac{1+9}{20}=\frac{10}{20}=\frac{1}{2}$