Решите уравнение 2x^2 +3x-3=x^2-3+(-2+x^2)

Question

Решите уравнение 2x^2 +3x-3=x^2-3+(-2+x^2)

Answer 1

2x^2 + 3x - 3 = x^2 - 3x - 2 + x^2
2x^2 + 3x - 3 = 2x^2 - 3x - 2
2x^2 - 2x^2 + 3x + 3x - 3 + 2 = 0
0 + 6x - 1 = 0
6x - 1 = 0 
6x = 1
x = 1/6

Answer 2

2х^2+3х-3-х^2+3+2-х^2=0
3х+2=0
3х=-2
х=-2/3