4 * 4^x - 5 * 2^x + 1=0

Question

4 * 4^x - 5 * 2^x + 1=0

Answer 1

2^x=t
4t^2-5t+1=0
D=25-4*4=9
t1,2=(5+-3)/8=1;1/4
2^x=1, x=0;
2^x=1/4, 2^x=2^-2, x=-2;
Ответ: 0; -2