Решите: 1) x^4<=625<br> 2)x^3>=216
X⁴-625≤0 (x²-25)(x²+25)≤0 x²+25≥0 при x∈(-∞;+∞) => x²-25≤0 (x-5)(x+5)≤0 x∈[-5;5] x³≥216 x³-216≥0 (x-6)(x²+6x+36)≥0 x²+6x+36=0 D=6²-4*36<0 => x²+6x+36>0 при x∈(-∞;+∞) => x-6≥0 x≥6