Как сделать это помогите пожалуйста

Решите задачу:

$173.\;a)\;-\frac34:\frac56-2\frac12\cdot\frac25+1:1\frac19=-\frac34\cdot\frac65-\frac52\cdot\frac25+1:\frac{10}9=\\=-\frac32\cdot\frac35-1+1\cdot\frac9{10}=-\frac9{10}-1+\frac9{10}=-1\\b)2\frac34:\left(-\frac25+1\frac12\right)-\left(-\frac34-\frac56\right):3\frac16=\frac{11}4:\left(-\frac25+\frac32\right)+\left(\frac9{12}+\frac{10}{12}\right):\frac{19}6=\\=\frac{11}4:\left(-\frac4{10}+\frac{15}{10}\right)+\frac{19}{12}\cdot\frac6{19}=\frac{11}4\cdot\frac{10}{11}+\frac12=\frac52+\frac12=3$
$c)\;\left(-\frac2{15}-1\frac7{12}\right)\cdot\frac{30}{103}+2:2\frac14\cdot\frac9{32}=\left(-\frac2{15}-\frac{19}{12}\right)\cdot\frac{30}{103}+2:\frac94\cdot\frac9{32}=\\=\left(-\frac8{60}-\frac{95}{60}\right)\cdot\frac{30}{103}+2\cdot\frac49\cdot\frac9{32}=\left(-\frac{103}{60}\right)\cdot\frac{30}{103}+\frac14=-\frac12+\frac14=-\frac14\\d)\;\left(-3\frac12:4\frac23-4\frac23:3\frac12\right)\cdot\left(-4\frac45\right)=\left(-\frac72:\frac{14}3-\frac{14}3:\frac72\right)\cdot\left(-\frac{24}5\right)=$
$=\left(-\frac72\cdot\frac3{14}-\frac{14}3\cdot\frac27\right)\cdot\left(-\frac{24}5\right)=\left(-\frac34-\frac43\right)\cdot\left(-\frac{24}5\right)=\\=\left(-\frac9{12}-\frac{16}{12}\right)\cdot\left(-\frac{24}5\right)=\left(-\frac{25}{12}\right)\cdot\left(-\frac{24}5\right)=\frac{25}5=5$