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$\frac{ c^{2}-1 }{ c^{2}-c } = \frac{(c-1)(c+1)}{c(c+1)} = \frac{c-1}{c} ;$
$\frac{4}{ c^{2}-( c-2)^{2} }= \frac{4}{(c-(c-2))(c+(c-2))}= \frac{4}{2(2c-2)}= \frac{4}{4(c-1)} = \frac{1}{c-1}$
получим
$\frac{(c-1)}{(c+1)}( \frac{c-1}{c}+ \frac{1}{c-1} )* (c+1)^{2} =( \frac{ (c-1)^{2} }{c(c+1)}+ \frac{1}{c+1})( c+1)^{2}$
$\frac{ (c-1)^{2}*(c+1) }{c} +c+1= \frac{(c-1)(c-1)(c+1)}{c} + \frac{ c^{2} }{c}+ \frac{c}{c} = \frac{ (c^{2}-1)(c-1)+ c^{2}+c }{c} =$
$= \frac{ c^{3}+1 }{c}= \frac{ c^{3} }{c} + \frac{1}{c} = c^{2} + \frac{1}{c}$
подставляем с=0,2
$0,2^{2} + \frac{1}{ \frac{2}{10} } =5+0,4=5,04$