(2а+1)(8а-1)+(4а-5)(3-2а)+12 при а=0

Question

(2а+1)(8а-1)+(4а-5)(3-2а)+12 при а=0

Answer 1

(2*0+1)(8*0-1)+(4*0-5)(3-2*0)+12=-1-15+12=-4

Answer 2

1*(-1)+(-5)*3+12=-4 ответ