Cos10x = cos5x
cos(2*5x) = cos5x
cos^2 5x - sin^2 5x - cos 5x = 0
cos^2 5x - (1 - cos^2 5x) - cos 5x = 0
cos^2 5x - 1 + cos^2 5x - cos 5x = 0
2cos^2 5x - cos 5x - 1 = 0 разделим на 2.
cos^2 5x - 0.5cos 5x - 0.5 = 0
По теореме Виета 1) сos 5x = 1, 5x = 2pin x = 2pin/5 x = 0.4pin
2) cos 5x = - 0.5 5x = +- 2pi/3 + 2pin x = +- 2pi/15 + 0.4pin
Ответ. 0,4pin; +- 2pi/5 + 0.4pin, где n принадлежит Z/