Помогите решить Систему уравнений(

$\left \{ {{x+y=2} \atop { 3^{6-x} * 4^{y+3} =36}} \right. \\ \left \{ {{x=2-y} \atop { 3^{6}* 3^{-x} * 4^{y}* 4^{3} =36}} \right. \\ \left \{ {{x=2-y} \atop { 3^{6}* 3^{y-2} * 4^{y}* 4^{3} =36}} \right. \\ \left \{ {{x=2-y} \atop { 3^{4}* 3^{y} * 4^{y}* 4^{3} =36}} \right. \\ \left \{ {{x=2-y} \atop { 3^{4}* 12^{y} * 4^{3} =36}} \right. \\ \left \{ {{x=2-y} \atop {12^{y} = \frac{3*12}{3^{4}*4^{3}} } \right. \\[tex] \left \{ {{x=2-y} \atop {12^{y} = \frac{1}{12^{2}} } \right. \\ \left \{ {{x=2-y} \atop {12^{y} = 12^{-2} } \right. \\ \left \{ {{x=2-y} \atop {y = -2 } \right. \\ \left \{ {{x=4} \atop {y = -2 } \right.$ [/tex]