ОДЗ:2х+7>0
2х> -7 Х> -3,5
log1/2 (2x+7)^1/3 <= -<br>log1/2 1/2
log1/2 (2x+7)^1/3 <=log1/2(1/2)^-1<br>(2x+7)^1/3 <= 2<br>2x+7<=8<br>2x <= 1<br>X<=1/2<br>///////////////////////
-----(-3,5)--------(1/2)-----
\\\\\\\\\\\\\\\\\\\\\\
Ответ: (-3,5 ; 1/2]
ОДЗ Х>0
lg9^1/2-lgx>lg3
lg 3/x>lg3
3/Х>3
3х<3<br>Х<1<br>Х€(0;1)