Sin(pi/18-8x)＝1 помогите решить.срочно надо
Решение Sin(π/18-8x)＝1 - sin(8x - π/18) = 1 sin(8x - π/18) = - 1 8x - π/18 = - π/2 + 2πk, k ∈ Z 8x = - π/2 + π/18 + 2πk, k ∈ Z 8x = - 8π/18 + 2πk, k ∈ Z x = - π/18 + πk/4, k ∈ Z