(2√125+2√20-2√80)/3√5

Question

(2√125+2√20-2√80)/3√5

Answer 1

2 V 125 = 10 V 5
2 V 20 = 4 V 5
2 V 80 = 8 V 5
10 V 5 + 4 V 5 - 8 V 5 = 6 V 5
( 6 V 5 ) : ( 3 V 5 ) = 2
Ответ 2

Answer 2

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