Д) Е) Ж) З)

Решите задачу:

$4x^{2}-12x+9\textgreater0,\\ (2x)^2-2\cdot2x\cdot3+3^2\ \textgreater \ 0, \\ (2x-3)^2\ \textgreater \ 0, \\ 2x-3\neq0, \\ x\neq1,5;$

$25x^{2}+30x+9\textless0, \\ (5x)^{2}+2\cdot5x\cdot3+3^2\textless0, \\ (5x+3)^2\textless0, \\ x\in\varnothing;$

$-10x^{2}+9x\textgreater0, \\ -10x(x-0,9)\textgreater0, \\ x(x-0,9)\textless0, \\ 0\textless x\textless0,9, \\ x\in(0;0,9);$

$-2x^2+7x\ \textless \ 0, \\ -2x(x-3,5)\ \textless \ 0, \\ x(x-3,5)\ \textgreater \ 0, \\ \left [ {{x\ \textless \ 0,} \atop {x\ \textgreater \ 3,5;}} \right. \\ x\in(-\infty;0)\cup(3,5;+\infty).$