0\\ sinx=-cosx\\ x=-\frac{\pi}{4}+\pi\*n\\ net\\ 2)-sinx=-cosx\\ x=\frac{-3\pi}{4}+\pi\*n\\ x=\frac{3\pi}{4}+\pi\*n" alt="|sinx|+cosx=0\\ 1)sinx>0\\ sinx=-cosx\\ x=-\frac{\pi}{4}+\pi\*n\\ net\\ 2)-sinx=-cosx\\ x=\frac{-3\pi}{4}+\pi\*n\\ x=\frac{3\pi}{4}+\pi\*n" align="absmiddle" class="latex-formula">