Log2(7x-4)=log2 13 помогите
Log2(7x-4)=log2(13), log2(7x-4)=log2(13), x>4/7, 7x-4=13, x=17/7, x>4/7, x=17/7
Log2 (7x-4) = log2 (13) => 7x-4 = 13 7x = 13+4 7x = 17 x = 17/7 x = 2 целые 3/7 Ответ: 2 целые 3/7