45 баллов плиз помогите :)

Решите задачу:

$y^1^7:y^5=y^1^7^-^5=y^1^2$

$x^2*x^8:x=x^2^+^8^-^1=x^9$

$(xyz)^3=x^3y^3z^3$

$\frac{a^4*(a^2)^3}{(a^5)^2}= \frac{(a^2)^2*(a^2)^3}{a^5^*^2}= \frac{(a^2)^2^+^3}{a^1^0}= \frac{(a^2)^5}{a^1^0} = \frac{a^2^*^5}{a^1^0}= \frac{a^1^0}{a^1^0}=1$

$\frac{(3^2)^3*(3^3)^4}{(3*3^2)^6}= \frac{3^2^*^3*3^3^*^4}{(3^3)^6}= \frac{3^6*3^1^2}{3^3^*^6}= \frac{3^6^+^1^2}{3^1^8}= \frac{3^1^8}{3^1^8}=1$

$\frac{(4^2)^3*(4^5)^2}{(4*4^2)^5}= \frac{4^2^*^3^+^5^*^2}{4^3^*^5}= \frac{4^1^6}{4^1^5}=4^1^6^-^1^5=4$

$(a^3)*(2a^2)^2=a^3*4a^4=4a^3^+^4=4a^7$

$(a^3)^2*a^1^8=a^3^*^2^+^1^8=a^2^4$