(x+4)(x+3)=(2-x)(7-x)
(х+4)(х+3)=(2-х)(7-х) х²+3х+4х+12=14-2х-7х+х² х²+7х+12=х²-9х+14 х²+7х+12-х²+9х-14=0 16х-2=0 16х=2 х=0,125