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7. M(NH4Cl)=52.5g/mol 160.5g xL 2NH4Cl+Ca(OH)2=CaCl2+2NH3+2H2O 105g 44.8L x=160.5*44.8/105=68.48L 6. M(Ca3P2)=40*3+31*2=182g/mol M(PH3)=31+3=34g/mol 1.75g xg Ca3P2+6H2O=2PH3+3Ca(OH)2 182g 68g x=1.75*68/182=0.65g