3X^2+40X+10 < -X^2+11X+3

Question

3X^2+40X+10 < -X^2+11X+3

Answer 1

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3х²+40х+10<-х²+11х+3<br>4х²29х+7<0<br>Y=x²+29x+7
D(y)=R
2)4x²+29x+7'=0
D=841-112=729
X1=-29+27/8=-1/4
X2=-29-27/8=-7


x€(-7;-1/4)