Срочно! (1–x+x^2)(6+x–x^2)=10

Question

Срочно!

(1–x+x^2)(6+x–x^2)=10

Answer 1

(1–x+x^2)(6+x–x^2)=10
(x²-x+1)(x²-x-6)=-10
x²-x-6=a⇒x²-x+1=a+7
a(a+7)+10=0
a²+7a+10=0
a1+a2=-7 U a1*a2=10
a1=-5⇒x²-x-6=-5
x²-x-1=0
D=1+4=5
x1=(1-√5)/2 U x2=(1+√5)/2
a2=-2⇒x²-x-6=-2
x²-x-4=0
D=1+16=17
x1=(1-√17)/2 U x2=(1+√17)/2