(x^2)(x^2+3)+(x^2+2)(x^2-3)(8x-4)(2x+5)+25=4x (4x-2)5an^2+5bn^2-bn-an+5cn^2-cn

Question

(x^2)(x^2+3)+(x^2+2)(x^2-3)

(8x-4)(2x+5)+25=4x (4x-2)

5an^2+5bn^2-bn-an+5cn^2-cn

Answer 1

(x^2) (1+3) + (x^2) (1+2) (1- 3) = 4(x^2) +6(x^2) = 10(x^2)
(8x-4)(2x+5)+25- 4x (4x-2) = 2х(4+1) (5-4) + 25 - 4х*2(2х-1) = 10х + 25 -16х +8х = 2х + 25