1) (1/4)^x=(1/5)^x 2)0,3^6x-1-0,3^6x>=0,7 Помогите решить ))))

$\displaystyle \frac{1}{4}^x= \frac{1}{5}^x$

т.к. 1/4≠1/5

то х=0

$\displaystyle 11^{-7x+1} \leq 121^{-2x-10} 11^{-7x+1} \leq 11^{-4x-20} -7x+1 \leq -4x-20 -3x \leq -21 x \geq 7$

$\displaystyle 0.09^{5x-1}\ \textless \ 0.3{x+7} 0.03^{10x-2}\ \textless \ 0.3^{x+7}$

$\displaystyle 10x-2\ \textgreater \ x+7$

$\displaystyle 9x\ \textgreater \ 9$
$\displaystyle x\ \textgreater \ 1$

$\displaystyle 0,3^{6x-1}-0.3^{6x} \geq 0.7 0.3^{6x}(1/0.3-1) \geq 0.7 0.3^{6x}(0.7/0.3) \geq 0.7 0.3^{6x} \geq 0.3 6x \leq 1 x \leq 1/6$