(b+6)^2= a(3a^2+a)= (p^2-pg+g^2) (p+g)=

Question

(b+6)^2=

a(3a^2+a)=

(p^2-pg+g^2) (p+g)=

Answer 1

b^2+12b+36

3a^3+a^2

p^3+g^3

Answer 2

(b + 6)^2 =b^2 + 12b + 36

a(3a^2+a) = 3a^3 + a^2

(p^2-pg+g^2)(p+g) = p^3+ gp^2-gp^2-pg^2 + pg^2 + g^3= p^3 + g^3