1\\\sin x=\frac12\Rightarrow x=\frac{\pi}6+2\pi n\\x\in[-\pi;2\pi]\Rightarrow x=\frac{\pi}6;\quad x=\frac{5\pi}6" alt="\\4\sin^2x-12\sin x+5=0\\\sin x=t,\quad t\in[-1;1]\\4t^2-12t+5=0\\D=144-4\cdot4\cdot5=64\\t_1=\frac12\\t_2=2,5>1\\\sin x=\frac12\Rightarrow x=\frac{\pi}6+2\pi n\\x\in[-\pi;2\pi]\Rightarrow x=\frac{\pi}6;\quad x=\frac{5\pi}6" align="absmiddle" class="latex-formula">