Решите уравнение log3 x+log3 x^2=-1
Loqa b+ loga c=loga b*c log3 x*x²=- 1 log3 x³=-1 x³=3^(-1)=1/3 x=∛(1/3)=1/∛3 проверка log3 (1/∛3)+ log3 (1/∛3)²=-1/3-2/3=-3/3=-1