Найти интеграл ∫(((x^(-1/3))-1)/(\sqrt[3]{x^{2}}))dx

Решите задачу:

$\int{\frac{x^{-\frac{1}{3}}-1}{\sqrt[3]{x^{2}}}}\, dx=\int{\frac{x^{-\frac{1}{3}}}{\sqrt[3]{x^{2}}}}\, dx - \int{\frac{1}{\sqrt[3]{x^{2}}}}\, dx=\int{\frac{x^{-\frac{1}{3}}}{x^{\frac{2}{3}}}\, dx - \int{\frac{1}{x^{\frac{2}{3}}}\, dx=$ $\int{x^{-1}}\, dx - \int{x^{-\frac{2}{3}}}\, dx=ln{x}-\frac{x^{\frac{1}{3}}}{\frac{1}{3}}+C=ln{x}-3*x^{\frac{1}{3}}+C$