(√z+2)(z-2√z+4) pj pomogite

Question

(√z+2)(z-2√z+4) pj pomogite

Answer 1

(a+b)*(a²-ab+b²)=a³+b³ сумма кубов

(√a)²=a

(√z+2)*(z-2√z+4)=(√z+2)*((√z)²-√z*2+2²)=(√z)³+2³=z*√z+8