222x+4=1100(5) 441x+14(10)=252(7) 44(x+5)-44(5)=52(10)

Question

222x+4=1100(5)
441x+14(10)=252(7)
44(x+5)-44(5)=52(10)

Answer 1

1.

2x^2 + 2x + 2 + 4 = 1*5^3 +1*5^2 { x > 2 }
2x^2 + 2x + 6 - 150 = 0
x^2 + x - 72 = 0
(x + 9)(x - 8) = 0
x = 8

2.

4x^2 + 4x + 1 + 14 = 2*7^2 + 5*7 + 2 { x > 4 }
4x^2 + 4x + 15 - 135 = 0
x^2 + x - 30 = 0
(x + 6)(x - 5) = 9
x = 5

3.

4(x+5) + 4 - 4*5 - 4 = 52 { x + 5 > 4 -> x > -1}
4x + 24 - 24 = 52
x = 13