W(C)=54,55% W(H)=9,09% W (O)=36,36% p(H2O)=22 CxHy-? Срочно

Question

W(C)=54,55%
W(H)=9,09%
W (O)=36,36%
p(H2O)=22
CxHy-?
Срочно

Answer 1

M(CxHyOz)=2*22=44
CxHyOz/44= 0.5455 / 12 : 0.0909/1 : 0.3636/16 
CxHyOz=2 : 4 : 1
C2H4O 
CH3-COH- этаналь или ацетатальдегид