F(x)=sin(2x+1)-3cos(1-x)

Question

F(x)=sin(2x+1)-3cos(1-x)

Answer 1

может так 

f(x)=sin(2x+1)-3cos(1-x)

f(x)+3 cos(1-x) = sin(2 x+1)

f(x)=-sin(1)sin^2(x)-3sin(1)sin(x)-3cos(1)cos(x)+sin(1)cos^2(x)+2cos(1)sin(x)cos(x)

f(x)=-3/2 e^(i-i x)-3/2 e^(-i+i x)+1/2 i e^(-i-2 i x)-1/2 i e^(i+2 i x)