(x+5)(x−8)<0<br>
x2−3x−40<0<br>
Let's find the critical points of the inequality.
x2−3x−40=0
(x+5)(x−8)=0
x+5=0 or x−8=0
x=−5 or x=8
x<−5<br>
−5
x>8
Answer:
−5
(x+2)(x−7)>0
x2−5x−14>0
x2−5x−14=0
(x+2)(x−7)=0
x+2=0 or x−7=0
x=−2 or x=7
x<−2<br>
−2
x>7
Answer:
x<−2 or x>7