Дискриминант = 169-144=25
x₁
x₂[tex] \frac{13- \sqrt[2]{D} }{6} = \frac{13-5}{6} = \frac{8}{6} =1[tex] \frac{1}{3} " alt=" \frac{13+ \sqrt[2]{D} }{6} = \frac{13+5}{6} = \frac{18}{6} =3 x₂[tex] \frac{13- \sqrt[2]{D} }{6} = \frac{13-5}{6} = \frac{8}{6} =1[tex] \frac{1}{3} " align="absmiddle" class="latex-formula">