(x^2+2x)^2-3=2(x^2+2x)

Question

(x^2+2x)^2-3=2(x^2+2x)

Answer 1

(х²+2х)²-3=2(х²+2х)
х²+2х=t
t²-3=2t
t²-2t-3=0
D=4+12=16
t₁= 2-4 / 2 = -1
t₂= 2+4 / 2 = 3

x²+2x=-1
x²+2x+1=0
D=4-4=0
x₁ = -2/2 = -1

x²+2x=3
x²+2x-3=0
D=4+12=16
x₂= -2-4 / 2 = -3
x₃= -2+4 / 2 = 1
Ответ: х₁=-1, х₂=-3, х₃=1