Решите неравенства: 3(2+х)>4-х -(4-х)меньше или равно2(3+х) 5х/2 > 1 5+3х/2 < 1

1 неравенство:
$3(2+x)\ \textgreater \ 4-x\\6+3x\ \textgreater \ 4-x\\4x\ \textgreater \ -2\\x\ \textgreater \ -\frac{2}{4}$
x∈(–0,5; +∞)

2 неравенство:
$-(4-x)\leq2(3+x)\\-4+x\leq6+2x\\-10\leq x$
x∈[–10; +∞)

3 неравенство:
$\frac{5x}{2}\ \textgreater \ 1\\2,5x\ \textgreater \ 1\\x\ \textgreater \ 0,4$
x∈(0,4; +∞)

4 неравенство:
$\frac{5+3x}{2}\ \textless \ 1\\5+3x\ \textless \ 2\\3x\ \textless \ -3\\x\ \textless \ -1$
x(–∞; –1)