Помогите решить!цена 25 баллов!

Решите задачу:

$\displaystyle 1).. \sqrt[3]{2ab}* \sqrt[3]{4a^{2}b }* \sqrt[3]{27b}=3 \sqrt[3]{8a^{3}b^{3}}=6ab; \\ \\ 2)..\sqrt[4]{abc}* \sqrt[4]{a^{3}b^{2}c}* \sqrt[4]{b^{5}c^{2}}= \sqrt[4]{a^{4}b^{8}c^{4}}=ab^{2}c; \\ \\ 3).. \sqrt[3]{ \sqrt[3]{a^{18} } }+(\sqrt{ \sqrt[3]{a^{4} } })^{3}= \sqrt[3]{a^{6}}+ (\sqrt[6]{a^{4} })^{3}=a^{ \frac{6}{3} }+a^{ \frac{12}{6}}=a^{2}+a^{2}=2a^{2}; \\ \\$
$\displaystyle 4)..(\sqrt{\sqrt[3]{x^{2}}})^{3}+2(\sqrt[4]{\sqrt{x}})^{8}= x^{\frac{6}{6}}+2x^{\frac{8}{8}}=x+2x=3x;\\\\5)..\sqrt[3]{\sqrt{x^{6}y^{12} }}-( \sqrt[5]{xy^{2}})^{5}=x^{\frac{6}{6}}y^{\frac{12}{6}}-(xy^{2})^{\frac{5}{5}}=xy^{2}-xy^{2}=0;\\\\6)..((\sqrt[5]{a\sqrt[5]{a}})^{5}-\sqrt[5]{a}):\sqrt[10]{a^{2}}=((a \sqrt[5]{a})^{\frac{5}{5}}-\sqrt[5]{a}):a^{\frac{2}{10}}=\\\\=(a\sqrt[5]{a}-\sqrt[5]{a})*a^{\frac{10}{2}}=a^{\frac{1}{5}}(a-1)*a^{5}=a^{\frac{5}{5}}(a-1)=a-1;$