(m^1/2n^-2-n^-3/2) делить m^3/4-m^1/4n^1/2 при m=81 n=0,1

Question

(m^1/2n^-2-n^-3/2) делить m^3/4-m^1/4n^1/2
при m=81 n=0,1

Answer 1

(m^1/2 n^(-2) - n^(-3/2)) / (m^3/4 - m^1/4 n^1/2)  =  (m^1/2 : n^2 - 1:n^3/2) /     /m^1/4(m^1/2 - n^1/2) = (m^1/2 - n^1/2) / n^2 * 1 / m^1/4(m^1/2 - n^1/2)  =       =  1 : (n^2 * m^1/4)  при  m  =  81,   n  =  0.1   Получим
1 : (0.1^2 * 81^1/4)  =  1/ 0.03 = 100/3  =  33 1/3